Walks ruin Burnett’s start, Yanks lose 7-2

A.J. Burnett was cruising well into the fourth inning Thursday afternoon at Yankee Stadium against the Texas Rangers.  In fact, he was perfect through 3 2/3 innings.  However, after two two-out walks, Burnett gave up a three-run home run to Ian Kinsler.  After that, the Rangers were well on their way to a 7-2 victory.

It wasn’t all Burnett’s fault.  The Yankees left 12 runners on base and couldn’t capitalize on starter Dustin Nippert’s seven walks.

Burnett was done after six innings.  He struck out a season-high 12 and only allowed two hits, but the three-run home run he allowed was more than enough to cause the defeat with the lack of run support he received.

Once Burnett was out, Phil Coke allowed a three-run home run to Nelson Cruz and Kinsler added his second home run of the game against David Robertson.

The Yankees will look to rebound tomorrow when they begin a three-game series against the Chicago White Sox.  CC Sabathia gets the start.